1) B
If height path the end of first year = 1m, then height at start of second year would also = 1m
Maximum theoretical height of tree = 30m
Difference between 30 and 1 = 30 – 1 = 29m
Since the growth will be 10% of the difference, growth in second year = 10% of 29 = 2.9 m
Height at the start of third year = 1 + 2.9 = 3.9m
Difference = 30 – 3.9 = 26.1m
10% = 2.61m
Total height = 3.90 + 2.61 = 6.51 m
To the nearest 10 cm, this will be 6.5 m
So the answer would be B
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