This can only be solved by visualisation.
We can eliminate A and C easily though. Look at the original die. The orientation between 5 and 6 is different in the original die as compared to A and C.
B has the same orientation of 3 as it is in the original die. This is only possible when the die is rotated in the same direction twice. Since it was rotated in a different direction, B is worn.g
In E, none of the original numbers are present on the die. At least one of the original number should have remained after 2 rotations, no matter the direction. So E is wrong.
We are left with D.